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JEE Mains · Maths · STD 11 - 7. binomial theoram

\((1 + x)^2 (1 + x^2)^3 ( 1 + x^3)^4\) ના વિસ્તરણમાં \(x^{10}\) નો સહગુણક મેળવો.

  1. A \(52\)
  2. B \(44\)
  3. C \(50\)
  4. D \(56\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(52\)

Step-by-step Solution

Detailed explanation

\(\because(1+x)^{2}=1+2 x+x^{2},\) \(\left(1+x^{2}\right)^{3}=1+3 x^{2}+3 x^{4}+x^{6},\) and \(\left(1+x^{3}\right)^{4}=1+4 x^{3}+6 x^{6}+4 x^{9}+x^{12}\) So, the possible combinations for \(x^{10}\) are:…
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