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JEE Mains · Maths · STD 12 - 6. Application of derivatives

જો વક  \(x=12(t+\sin t \cos t)\), \(y =12(1+\sin t )^{2}, 0 < t < \frac{\pi}{2}\) પરનાં  બિંદુ,  \(\left(x_{0}, y_{0}\right)\) આગળનો સ્પર્શક એ \(x\)-અક્ષની ધન દિશા સાથે \(\frac{\pi}{3}\) જેટલો ખૂણો બનાવે, તો \(y _{0}\) = ............

  1. A \(6(3+2 \sqrt{2})\)
  2. B \(3(7+4 \sqrt{3})\)
  3. C \(27\)
  4. D \(48\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(27\)

Step-by-step Solution

Detailed explanation

\(\frac{d y}{d x}=\frac{2(1+\sin t) \times \cos t}{1+\cos 2 t}\) \(\Rightarrow \frac{2(1+\sin t) \cos t}{2 \cos ^{2} t}=\sqrt{3}\) \(\Rightarrow t =\frac{\pi}{6}, y _{0}=27\)
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