ExamBro
ExamBro
JEE Mains · Maths · STD 12 - 6. Application of derivatives

यदि वक्र \(x=12(t+\sin t \cos t)\),\(y =12(1+\sin t )^2, 0 < t < \frac{\pi}{2}\) के बिन्दु \(\left( x _0, y _0\right)\)पर स्पर्श रेखा द्वारा, धनात्मक \(x\)-अक्ष के साथ बनाया गया कोण \(\frac{\pi}{3}\) हो तो \(y _0\) बराबर होगा-

  1. A \(6(3+2 \sqrt{2})\)
  2. B \(3(7+4 \sqrt{3})\)
  3. C \(27\)
  4. D \(48\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(27\)

Step-by-step Solution

Detailed explanation

\(\frac{d y}{d x}=\frac{2(1+\sin t) \times \cos t}{1+\cos 2 t}\) \(\Rightarrow \frac{2(1+\sin t) \cos t}{2 \cos ^{2} t}=\sqrt{3}\) \(\Rightarrow t =\frac{\pi}{6}, y _{0}=27\)
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app