જો \(S = \{1, 2, 3, ….., 100\}\). જ્યાં \(A\) માં રહેલા બધા ઘટકો નો ગુણાકાર યુગ્મ આવે એવા \(S\) ના ખાલી ગણ ના હોય એવા ઉપગણો \(A\) ની સંખ્યા મેળવો

A \(2^{100} -1\)
B \(2^{50} (2^{50} -1)\)
C \(2^{50} -1\)
D \(2^{50} + 1\)

Verified Solution

Answer & Solution

Correct Answer

(B) \(2^{50} (2^{50} -1)\)

Step-by-step Solution

Detailed explanation

Product is even when atleast one element of subset is even Hence required number of subsets = total subsets -number of subsets all whose elements are odd \(= 2^{100} - 2^{50}\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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