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JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant

જો સમીકરણ સંહતિ \(x+y+z=6 \,; \,2 x+5 y+\alpha z=\beta  \,; \, x+2 y+3 z=14\) એ અનંત ઉકેલ ધરાવે છે તો  \(\alpha+\beta\) ની કિમંત મેળવો.

  1. A \(8\)
  2. B \(36\)
  3. C \(44\)
  4. D \(48\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(44\)

Step-by-step Solution

Detailed explanation

\(x+y+z=6\) \(2 x+5 y+\alpha z=\beta \quad(1)\) \(x+2 y+3 z=14\) \(x+y=6-z\) \(x+2 y=14-3 z\) On solving \(x=z-2 \Rightarrow y=8-2 z\) in \((2)\) \(2(z-2)+5(8-2 z)+\alpha z=\beta\) \((\alpha-8) z=\beta-36\) For having infinite solutions \(\alpha-8=0 \quad \& \quad \beta-36=0\)…
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