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JEE Mains · Maths · STD 11 - 8. sequence and series

જો \([\mathrm{x}]\) એ \(\mathrm{x}\) નું મહતમ પૃણાંક વિધેય છે તો  \(\sum_{\mathrm{n}=8}^{100}\left[\frac{(-1)^{n} \mathrm{n}}{2}\right]\) ની કિમંત મેળવો.

  1. A \(-2\)
  2. B \(4\)
  3. C \(2\)
  4. D \(0\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(4\)

Step-by-step Solution

Detailed explanation

\(\sum_{n=8}^{100}\left[\frac{(-1)^{n} \cdot n}{2}\right]=\left[\frac{8}{2}\right]+\left[\frac{-9}{2}\right]+\left[\frac{10}{2}\right]+\left[\frac{-11}{2}\right]+\ldots+\ldots\left[\frac{-99}{2}\right]+\left[\frac{100}{2}\right]\) \(=4-5+5-6+6+\ldots-50+50=4\)
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