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JEE Mains · Maths · STD 11 - 9. straight line

ધારો કે વિધેય \(f(x)=6+16 \cos x \cdot \cos \left(\frac{\pi}{3}-x\right) \cdot \cos \left(\frac{\pi}{3}+x\right) \cdot \sin 3 x \cdot \cos 6 x, x \in \mathbf{R}\) નો વિસ્તાર \([\alpha, \beta]\) છે. તો બિંદુ \((\alpha, \beta)\) થી રેખા \(3 x+4 y+12=0\) નું અંતર કેટલું છે?

  1. A 11
  2. B 8
  3. C 10
  4. D 9
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Answer & Solution

Correct Answer

(A) 11

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Detailed explanation

\begin{aligned} & f(x)=6+16 \cos x \cdot \cos \left(\frac{\pi}{3}-x\right) \\ & \qquad \cos \left(\frac{\pi}{3}+x\right) \cdot \sin 3 x \cdot \cos 6 x \\ & f(x)=6+4 \cos 3 x \cdot \sin 3 x \cdot \cos 6 x \\ & \therefore \quad f(x)=6+\sin 12 x \\ & \therefore \quad \text { Range…

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