ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Maths · STD 12 - 11. three dimension geometry

જો રેખા \(\frac{{x + 1}}{2} = \frac{{y - 2}}{1} = \frac{{z - 3}}{{ - 2}}\) અને સમતલ  \(x\,\, - \,2y\, - \,kz\, = \,3\) વચ્ચેનો ખૂણો \({\cos ^{ - 1}}\,\left( {\frac{{2\sqrt 2 }}{3}} \right)\) હોય તો  \(k\) મેળવો.

  1. A \(\sqrt {\frac{5}{3}} \)
  2. B \(\sqrt {\frac{3}{5}} \)
  3. C \( - \frac{3}{5}\)
  4. D \( - \frac{5}{3}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\sqrt {\frac{5}{3}} \)

Step-by-step Solution

Detailed explanation

Direction Ratio of line are \(2,1,-2\) Normal vector of plane is \(\hat{\mathrm{i}}-2 \hat{\mathrm{j}}-\mathrm{k} \hat{\mathrm{k}}\) \(\sin \alpha=\frac{(2 \hat{i}+\hat{j}-2 \hat{k}) \cdot(\hat{i}-2 \hat{j}-k \hat{k})}{3 \sqrt{1+4+k^{2}}}\)…
From JEE Mains
Explore more questions on app