ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola

જો પરવલય \(y^2 = x\) એ બિંદુ \(\left( {\alpha ,\beta } \right)\,,\,\left( {\beta  > 0} \right)\) અને ઉપવલય \(x^2 + 2y^2 = 1\) આગળનો સ્પર્શક હોય તો \(a\) = 

  1. A \(2\sqrt 2  + 1\)
  2. B \(\sqrt 2  - 1\)
  3. C \(\sqrt 2  + 1\)
  4. D \(2\sqrt 2  - 1\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\sqrt 2  + 1\)

Step-by-step Solution

Detailed explanation

Equation of tangent to the parabola \({y^2} = x\) \(At\left( {\alpha ,\beta } \right)\) is \(T=0\) \(y\beta = \frac{{x + \alpha }}{2}\) \( \Rightarrow y\beta = \frac{{x + {\beta ^2}}}{2}\,\) (\(\because\) \({\beta ^2} = \alpha \))…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app