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JEE Mains · Maths · STD 12 - 11. three dimension geometry

સમતલ \(x - y + z = 5\) થી રેખા \(x = y = z\) ની દિશામાં માપવામાં આવેલ બિંદુ \(\left( {1, - 5,9} \right)\)નું અંતર . . . .છે.

  1. A \(\frac{{10}}{{\sqrt 3 }}\)
  2. B \(\frac{{20}}{3}\)
  3. C \(3\sqrt {10} \)
  4. D \(\;10\sqrt 3 \)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\;10\sqrt 3 \)

Step-by-step Solution

Detailed explanation

Equation of line parallel to \(x=y=z\) through \((1,-5,9)\) is \(\frac{x-1}{1}=\frac{y+5}{1}=\frac{z-9}{1}=\lambda\) If \(\mathrm{P}(\lambda+1, \lambda-5, \lambda+9)\) be point of intesection of line and plane. \(\Rightarrow \lambda+1-\lambda+5+\lambda+9=5\)…
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