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JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations

જો \(\alpha, \beta\) એ સમીકરણ \(x^{2}+5 \sqrt{2} x+10=0, \alpha\,>\,\beta\) ના બીજ છે અને દરેક ધન પૃણાંક \(n\) માટે  \(P_{n}=\alpha^{n}-\beta^{n}\) હોય તો \(\left(\frac{P_{17} P_{20}+5 \sqrt{2} P_{11} P_{19}}{P_{18} P_{19}+5 \sqrt{2} P_{18}^{2}}\right)\) ની કિમંત મેળવો.

  1. A \(4\)
  2. B \(3\)
  3. C \(2\)
  4. D \(1\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(1\)

Step-by-step Solution

Detailed explanation

\(x^{2}+5 \sqrt{2} x+10=0\) \(\& p_{n}=\alpha^{n}-\beta^{n} \text { (Given) }\) \(\text { Now } \frac{P_{17} P_{20}+5 \sqrt{2} p_{11} P_{19}}{P_{18} P_{19}+5 \sqrt{2} P_{18}^{2}}=\frac{P_{17}\left(P_{20} 5 \sqrt{2} P_{19}\right)}{P_{18}\left(P_{19}+5 \sqrt{2 P}_{18}\right)}\)…
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