JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations
If \(\alpha, \beta\) are roots of the equation \(x^{2}+5 \sqrt{2} x+10=0, \alpha\,>\,\beta\) and \(P_{n}=\alpha^{n}-\beta^{n}\) for each positive integer \(\mathrm{n}\), then the value of \(\left(\frac{P_{17} P_{20}+5 \sqrt{2} P_{11} P_{19}}{P_{18} P_{19}+5 \sqrt{2} P_{18}^{2}}\right)\) is equal to \(....\)
- A \(4\)
- B \(3\)
- C \(2\)
- D \(1\)
Answer & Solution
Correct Answer
(D) \(1\)
Step-by-step Solution
Detailed explanation
\(x^{2}+5 \sqrt{2} x+10=0\) \(\& p_{n}=\alpha^{n}-\beta^{n} \text { (Given) }\) \(\text { Now } \frac{P_{17} P_{20}+5 \sqrt{2} p_{11} P_{19}}{P_{18} P_{19}+5 \sqrt{2} P_{18}^{2}}=\frac{P_{17}\left(P_{20} 5 \sqrt{2} P_{19}\right)}{P_{18}\left(P_{19}+5 \sqrt{2 P}_{18}\right)}\)…
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