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JEE Mains · Maths · STD 12 - 1. relation and function

ધારો કે \(f : R \rightarrow R\) તથા \(g : R \rightarrow R\) એ  \(f(x)=\left\{\begin{array}{ll}x+a, & x<0 \\ |x-1|, & x \geq 0\end{array}\right.\) તથા  \(g(x)=\left\{\begin{array}{cc}x+1, & x<0 \\ (x-1)^{2}+b, & x \geq 0\end{array}\right.\) પ્રમાણે વ્યાખ્યાયિત છે, જ્યાં \(a, b\) અનૃણ (non-negative) વાસ્તવિક સંખ્યાઓ છે. જોં દરેક \(x \in R\) માટે \((gof)\,( x )\) સતત હોય, તો \(a + b =.....\)

  1. A \(2\)
  2. B \(1\)
  3. C \(4\)
  4. D \(3\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(1\)

Step-by-step Solution

Detailed explanation

\(g[f(x)]=\left[\begin{array}{cc}f(x)+1 & f(x)<0 \\ (f(x)-1)^{2}+b & f(x) \geq 0\end{array}\right.\)…
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