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JEE Mains · Maths · STD 11 - 1. set theory

જો \(A=\left\{n \in N \mid n^{2} \leq n+10,000\right\}, B=\{3 k+1 \mid k \in N\}\) અને \(C=\{2 k \mid k \in N\}\) હોય તો ગણ \(A \cap(B-C)\) ના બધાજ ઘટકોનો સરવાળો મેળવો.

  1. A \(832\)
  2. B \(412\)
  3. C \(963\)
  4. D \(123\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(832\)

Step-by-step Solution

Detailed explanation

\(\mathrm{B}-\mathrm{C} \equiv\{7,13,19, \ldots 97, \ldots\}\) Now, \(n^{2}-n \leq 100 \times 100\) \(\Rightarrow \mathrm{n}(\mathrm{n}-1) \leq 100 \times 100\) \(\Rightarrow \mathrm{A}=\{1,2, \ldots, 100\}\) So, \(A \cap(B-C)=\{7,13,19, \ldots, 97\}\) Hence, sum…
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