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JEE Mains · Maths · STD 12 - 10. vector algebra

જો \(a, b , c \in R\) એવા હોય કે જેથી \(a ^{2}+ b ^{2}+ c ^{2}=1\) અને \(a \cos \theta=b \cos \left(\theta+\frac{2 \pi}{3}\right)=\operatorname{ccos}\left(\theta+\frac{4 \pi}{3}\right)\) જ્યાં \(\theta=\frac{\pi}{9},\) હોય તો સદીશો \(a \hat{i}+b \hat{j}+c \hat{k}\) અને \(b \hat{i}+c \hat{j}+a \hat{k}\) વચ્ચેનો ખૂણો મેળવો.

  1. A \(\frac{\pi}{2}\)
  2. B \(0\)
  3. C \(\frac{\pi}{9}\)
  4. D \(\frac{2 \pi}{3}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{\pi}{2}\)

Step-by-step Solution

Detailed explanation

\(\cos \phi=\frac{\bar{p} \cdot \bar{q}}{|\bar{p}||\bar{q}|}=\frac{a b+b c+c a}{a^{2}+b^{2}+c^{2}}=\frac{\sum a b}{1}\) \(=\operatorname{abc}\left(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\right)\)…
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