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JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant

જો  \(A = \left[ {\begin{array}{*{20}{c}}
{\cos \,\theta }&{ - \sin \,\theta }\\
{\sin \,\theta }&{\cos \,\theta }
\end{array}} \right]\), તો શ્રેણિક  \({A^{ - 50}}\) મેળવો જો  \(\theta  = \frac{\pi }{{12}}\) હોય.

  1. A \(\left[ {\begin{array}{*{20}{c}} {\frac{1}{2}}&{ - \frac{{\sqrt 3 }}{2}}\\ {\frac{{\sqrt 3 }}{2}}&{\frac{1}{2}} \end{array}} \right]\)
  2. B \(\left[ {\begin{array}{*{20}{c}} {\frac{{\sqrt 3 }}{2}}&{ - \frac{1}{2}}\\ {\frac{1}{2}}&{\frac{{\sqrt 3 }}{2}} \end{array}} \right]\)
  3. C \(\left[ {\begin{array}{*{20}{c}} {\frac{{\sqrt 3 }}{2}}&{\frac{1}{2}}\\ { - \frac{1}{2}}&{\frac{{\sqrt 3 }}{2}} \end{array}} \right]\)
  4. D \(\left[ {\begin{array}{*{20}{c}} {\frac{1}{2}}&{\frac{{\sqrt 3 }}{2}}\\ { - \frac{{\sqrt 3 }}{2}}&{\frac{1}{2}} \end{array}} \right]\)
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Answer & Solution

Correct Answer

(C) \(\left[ {\begin{array}{*{20}{c}} {\frac{{\sqrt 3 }}{2}}&{\frac{1}{2}}\\ { - \frac{1}{2}}&{\frac{{\sqrt 3 }}{2}} \end{array}} \right]\)

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Detailed explanation

\(A = \left[ {\begin{array}{*{20}{c}} {\cos \theta }&{ - \sin \theta }\\ {\sin \theta }&{\cos \theta } \end{array}} \right]\)…
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