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JEE Mains · Maths · STD 12 - 1. relation and function

\(x \in \left( {0,\frac{3}{2}} \right)\) માટે \(f\left( x \right) = \sqrt x \), \(g\left( x \right) = \tan \,x\) અને \(h\left( x \right) = \frac{{1 - {x^2}}}{{1 + {x^2}}}\) છે . જો \(\phi \left( x \right) = \left( {\left( {hof} \right)og} \right)\left( x \right)\), તો \(\phi \left( {\frac{\pi }{3}} \right)\) મેળવો.

  1. A \(\tan \,\frac{{11\pi }}{{12}}\)
  2. B \(\tan \,\frac{\pi }{{12}}\)
  3. C \(\tan \,\frac{5\pi }{{12}}\)
  4. D \(\tan \,\frac{7\pi }{{12}}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\tan \,\frac{{11\pi }}{{12}}\)

Step-by-step Solution

Detailed explanation

\(f\left( x \right) = \sqrt x ,g\left( x \right) = \tan \,x,h\left( x \right) = \frac{{1 - {x^2}}}{{1 + {x^2}}}\) \(fog\left( x \right) = \sqrt {\tan x} \) \(hofog\left( x \right) = h\left( {\sqrt {\tan x} } \right) = \frac{{1 - \tan x}}{{1 + \tan x}}\)…
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