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JEE Mains · Maths · STD 12 - 7.2 definite integral

જો \(\int\limits_0^{\frac{\pi }{3}} {\frac{{\tan \,\,\theta }}{{\sqrt {2k\,\sec \,\theta } }}} \,d\theta \, = \,1 - \frac{1}{{\sqrt 2 }},(k > 0),\) તો \(k\) ની કિમંત મેળવો.

  1. A \(2\)
  2. B \(\frac {1}{2}\)
  3. C \(4\)
  4. D \(1\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(2\)

Step-by-step Solution

Detailed explanation

\(\frac{1}{{\sqrt {2k} }}\int\limits_0^{\pi /3} {\frac{{\tan \theta }}{{\sqrt {\sec \theta } }}} d\theta \) \( = \frac{1}{{\sqrt {2k} }}\int\limits_0^{\pi /3} {\frac{{\sin \theta }}{{\sqrt {\cos \theta } }}} d\theta \)…
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