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JEE Mains · Maths · STD 11 - 7. binomial theoram

ધારોકે \(S=\frac{1}{25!}+\frac{1}{3!23!}+\frac{1}{5!21!}+\ldots 13\) પદો સુધી. જો \(13 S=\frac{2^k}{n!}, k \in N\) હોય, તો \(n+k\) = ___ .

  1. A 51
  2. B 52
  3. C 49
  4. D 50
Verified Solution

Answer & Solution

Correct Answer

(C) 49

Step-by-step Solution

Detailed explanation

\(\frac{1}{26!}\left(\frac{26!}{25!1!}+\frac{26!}{3!23!}+\frac{26!}{5!21!}+\ldots . .+13\right.\) terms \()\)…
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