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JEE Mains · Maths · STD 12 - 7.1 indefinite integral

ધારોકે \(f(x)=\int \frac{d x}{\left(3+4 x^2\right) \sqrt{4-3 x^2}},|x| < \frac{2}{\sqrt{3}}\).જો \(f(0)=0\) અને \(f(1)=\frac{1}{\alpha \beta} \tan ^{-1}\left(\frac{\alpha}{\beta}\right), \alpha, \beta > 0\),તો \(\alpha^2+\beta^2 =.........\).

  1. A \(28\)
  2. B \(26\)
  3. C \(25\)
  4. D \(24\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(28\)

Step-by-step Solution

Detailed explanation

\(f(x)=\int \frac{d x}{\left(3+4 x^2\right) \sqrt{4-3 x^2}}\) \(x=\frac{1}{t}\) \(=\int \frac{\frac{-1}{t^2} d t}{\frac{\left(3 t^2+4\right)}{t^2} \frac{\sqrt{4 t^2-3}}{t}}\) \(=\int \frac{-d t \cdot t}{\left(3 t^2+4\right) \sqrt{4 t^2-3}}: \text { Put } 4 t^2-3=z^2\)…
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