ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Maths · STD 11 - 4.1 complex nubers

\(\frac{{2 + 3isin\;\theta }}{{1 - 2i\sin \theta }}\) એ \(\theta \) ની કઇ કિંમત માટે શુદ્વ કાલ્પનિક સંખ્યા છે?

  1. A \({\sin ^{ - 1}}\left( {\frac{{\sqrt 3 }}{4}} \right)\;\)
  2. B \(\;{\sin ^{ - 1}}\left( {\frac{1}{{\sqrt 3 }}} \right)\)
  3. C \(\frac{\pi }{3}\)
  4. D \(\;\frac{\pi }{6}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\;{\sin ^{ - 1}}\left( {\frac{1}{{\sqrt 3 }}} \right)\)

Step-by-step Solution

Detailed explanation

Purely imaginary means real part \(=0\) \( \frac{2+3 \sin \theta}{1-2 i \sin \theta} \times \frac{1+2 i \sin \theta}{1+2 i \sin \theta} \) \(=\frac{2+4 i \sin \theta+3 i \sin \theta-6 \sin ^{2} \theta}{1-(2 i \sin \theta)^{2}}\)…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app