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JEE Mains · Maths · STD 12 - 7.2 definite integral

ધારોકે \(f\) એવું એક બહુપદી વિધેય છે કે જેથી પ્રત્યેક \(x \in R\) માટે, \(f\left(x^2+1\right)=x^4+5 x^2+2\). તો \(\int_0^3 f(x) d x=\) ___ .

  1. A \(\frac{41}{3}\)
  2. B \(\frac{33}{2}\)
  3. C \(\frac{27}{2}\)
  4. D \(\frac{5}{3}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{33}{2}\)

Step-by-step Solution

Detailed explanation

\(\because f\left(x^2+1\right)=x^4+5 x^2+2\) \(\left\{\right.\)put \(\left.x ^2+1= t \right\}\) \(\Rightarrow f(t)=(t-1)^{2}+5(t-1)+2\) \(\Rightarrow f(t)=t^{2}+3t-2\) Now, \(\int_{0}^{3}f(t)dt=\int_{0}^{3}(t^{2}+3t-2)dt\) \([\frac{t^{3}}{3}+\frac{3t^{2}}{2}-2t]_{0}^{3}\)…
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