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JEE Mains · Maths · STD 12 - 1. relation and function

ધારોકે \(f\) એ પ્રત્યેક \(f(x+y)=f(x)+f(y)\) માટે \(x, y \in N\) અને \(f(1)=\frac{1}{5}\) નું સમાધાન કરતુ વિધેય છે. જો \(\sum \limits_{n=1}^m \frac{f(n)}{n(n+1)(n+2)}=\frac{1}{12}\) હોય, તો \(m=..........\)

  1. A \(11\)
  2. B \(12\)
  3. C \(10\)
  4. D \(13\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(10\)

Step-by-step Solution

Detailed explanation

\(\because f(1)=\frac{1}{5} \therefore f(2)=f(1)+f(1)=\frac{2}{5}\) \(f(2)=\frac{2}{5} \quad f(3)=f(2)+f(1)=\frac{3}{5}\) \(f(3)=\frac{3}{5}\) \(\therefore \sum \limits_{n=1}^m \frac{f(n)}{n(n+1)(n+2)}\)…
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