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JEE Mains · Maths · STD 12 - 1. relation and function

माना \(f\) एक फलन है जो सभी \(x, y \in \mathbb{N}\) के लिए \(\mathrm{f}(\mathrm{x}+\mathrm{y})=\mathrm{f}(\mathrm{x})+\mathrm{f}(\mathrm{y})\) को संतुष्ट करता है एवं \(\mathrm{f}(1)=\frac{1}{5}\) है यदि \(\sum_{\mathrm{n}=1}^{\mathrm{m}} \frac{\mathrm{f}(\mathrm{n})}{\mathrm{n}(\mathrm{n}+1)(\mathrm{n}+2)}=\frac{1}{12}\) हैं, तब \(\mathrm{m}\) बराबर है_________. 

  1. A \(11\)
  2. B \(12\)
  3. C \(10\)
  4. D \(13\)
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Answer & Solution

Correct Answer

(C) \(10\)

Step-by-step Solution

Detailed explanation

\(\because f(1)=\frac{1}{5} \therefore f(2)=f(1)+f(1)=\frac{2}{5}\) \(f(2)=\frac{2}{5} \quad f(3)=f(2)+f(1)=\frac{3}{5}\) \(f(3)=\frac{3}{5}\) \(\therefore \sum \limits_{n=1}^m \frac{f(n)}{n(n+1)(n+2)}\)…
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