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JEE Mains · Maths · STD 12 - 5. continuity and differentiation

અહી \([t]\) એ \(\leq t\) હોય તેવો પૃણાંક દર્શાવે છે. વિધેય \(f(x)=[x]\left|x^{2}-1\right|+\sin \left(\frac{\pi}{[x]+3}\right)-[x+1], x \in(-2,2)\) એ  .  . .  બિંદુઓએ સતત નથી.

  1. A \(2\)
  2. B \(4\)
  3. C \(6\)
  4. D \(8\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(2\)

Step-by-step Solution

Detailed explanation

\(f(x)=[x]\left|x^{2}-1\right|+\sin \frac{\pi}{[x+3]}-[x+1]\) \(f(x)=\{3-2 x^{2}, \quad\quad\quad-2\) \(\quad\quad\quad x^{2}, \quad\quad\,\,\quad\quad\quad -1 \leq x<0\) \(\quad\quad\quad \frac{\sqrt{3}}{2}+1 \quad\quad\quad\quad 0 \leq x<1\)…
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