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JEE Mains · Maths · STD 12 - 11. three dimension geometry

ધારો કે સમતલ \(P\) પરના બિંદુઓ \((-4,2,1)\) અને \((2,-2,3)\) બિંદુઓથી સમાન અંતરે આવવેાં છે. તો સમતલ \(P\) અને સમતલ \(2 x + y +\) \(3 z =1\) વચ્યેનો લધુકોણ.........છે

  1. A \(\frac{\pi}{6}\)
  2. B \(\frac{\pi}{4}\)
  3. C \(\frac{\pi}{3}\)
  4. D \(\frac{5 \pi}{12}\)
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Answer & Solution

Correct Answer

(C) \(\frac{\pi}{3}\)

Step-by-step Solution

Detailed explanation

Normal vector \(=\overrightarrow{ AB }=(\overrightarrow{ OB }-\overrightarrow{ OA })\) \(=(6 \hat{ i }-4 \hat{ j }+2 \hat{ k })\) or \(2(3 \hat{ i }-2 \hat{ j }+\hat{ k })\) \(P \equiv 3( x +1)-2( y )+1( z -2)=0\) \(P \equiv 3 x -2 y + z +1=0\)…
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