JEE Mains · Maths · STD 12 - 11. three dimension geometry
Let the points on the plane \(P\) be equidistant from the points \((-4,2,1)\) and \((2,-2,3)\). Then the acute angle between the plane \(P\) and the plane \(2 x + y +\) \(3 z =1\) is
- A \(\frac{\pi}{6}\)
- B \(\frac{\pi}{4}\)
- C \(\frac{\pi}{3}\)
- D \(\frac{5 \pi}{12}\)
Answer & Solution
Correct Answer
(C) \(\frac{\pi}{3}\)
Step-by-step Solution
Detailed explanation
Normal vector \(=\overrightarrow{ AB }=(\overrightarrow{ OB }-\overrightarrow{ OA })\) \(=(6 \hat{ i }-4 \hat{ j }+2 \hat{ k })\) or \(2(3 \hat{ i }-2 \hat{ j }+\hat{ k })\) \(P \equiv 3( x +1)-2( y )+1( z -2)=0\) \(P \equiv 3 x -2 y + z +1=0\)…
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