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JEE Mains · Maths · STD 12 - 5. continuity and differentiation

ધારો કે \(f(\mathrm{x})= \begin{cases}(1+\mathrm{ax})^{1 / \mathrm{x}} & , \quad \mathrm{x} \lt 0 \\ 1+\mathrm{b} & , \quad \mathrm{x}=0 \\ \frac{(\mathrm{x}+4)^{1 / 2}-2}{(\mathrm{x}+\mathrm{c})^{1 / 3}-2} & ,\end{cases}\)
\(x=0\) આગળ સતત હોય, તો \(e^a b c\) = ___

  1. A \(64\)
  2. B \(72\)
  3. C \(48\)
  4. D \(36\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(48\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & f\left(0^{-}\right)=\mathrm{e}^{\lim _{x \rightarrow 0} \frac{\mathrm{ax}}{\mathrm{x}}}=\mathrm{e}^{\mathrm{a}} \\ & \mathrm{f}(0)=1+\mathrm{b} \\ & \mathrm{f}\left(0^{+}\right)=\frac{\frac{1}{2…

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