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JEE Mains · Maths · STD 12 - 5. continuity and differentiation

ધારો કે દ્વિ-વિકલનીય વિધેય \(f : S \rightarrow S\) જ્યાં \(S =(0, \infty)\) માટે \(f ( x +1)= xf ( x )\) છે. જો \(g: S \rightarrow R\) એ \(g(x)=\log _{e} f(x)\) મુજબ વ્યાખ્યાયિત હોય, તો \(\mid g "(5)- g "(1) \mid\) ની કિંમત  ..... છે.

  1. A \(\frac{205}{144}\)
  2. B \(\frac{197}{144}\)
  3. C \(\frac{187}{144}\)
  4. D \(1\)
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Answer & Solution

Correct Answer

(A) \(\frac{205}{144}\)

Step-by-step Solution

Detailed explanation

\(\operatorname{lnf}(x+1)=\ln (x f(x))\) \(\operatorname{lnf}(x+1)=\ln x+\operatorname{lnf}(x)\) \(\Rightarrow g(x+1)=\ln x+g(x)\) \(\Rightarrow g(x+1)-g(x)=\ln x\) \(\Rightarrow \quad g^{\prime \prime}(x+1)-g^{\prime \prime}(x)=-\frac{1}{x^{2}}\) Put \(x=1,2,3,4\)…
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