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JEE Mains · Maths · STD 11 - 13. statistics

ધારો કે અવલોકનો  \(\mathrm{x}_{\mathrm{i}}(1 \leq \mathrm{i} \leq 10)\) એ સમીકરણો  \(\sum\limits_{i=1}^{10}\left(x_{i}-5\right)=10\) અને  \(\sum\limits_{i=1}^{10}\left(x_{i}-5\right)^{2}=40\) નું સમાધાન કરે છે. જો  \(\mu\) અને  \(\lambda\) એ અનુક્રમે અવલોકનો \(\mathrm{x}_{1}-3, \mathrm{x}_{2}-3, \ldots ., \mathrm{x}_{10}-3,\) નો મધ્યક અને વિચરણ હોય તો ક્રમયુક્ત જોડ \((\mu, \lambda)\) મેળવો.

  1. A \((6, 6)\)
  2. B \((3, 6)\)
  3. C \((6, 3)\)
  4. D \((3, 3)\)
Verified Solution

Answer & Solution

Correct Answer

(D) \((3, 3)\)

Step-by-step Solution

Detailed explanation

\(\sum_{i=1}^{10}\left(x_{i}-5\right)=10\) \(\Rightarrow\) Mean of observation \(\mathrm{x}_{\mathrm{i}}-5=\frac{1}{10} \sum_{\mathrm{i}=1}^{3}\left(\mathrm{x}_{\mathrm{i}}-5\right)=1\) \(\Rightarrow \mu=\) mean of observation \(\left(\mathrm{x}_{\mathrm{i}}-3\right)\)…
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