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JEE Mains · Maths · STD 11 - 13. statistics

माना प्रेक्षण \(x _{ i }(1 \leq i \leq 10)\) समीकरणों \(\sum_{ i =1}^{10}\left( x _{ i }-5\right)=10\) तथा \(\sum_{ i =1}^{10}\left( x _{ i }-5\right)^{2}=40\) को संतुष्ट करते है। यदि \(\mu\) तथा \(\lambda\) प्रेक्षणों \(x _{1}-3, x _{2}-3, \ldots, x _{10}-3\) के क्रमशः माध्य तथा प्रसरण है, तो क्रमित युग्म \((\mu, \lambda)\) बराबर है 

  1. A \((6, 6)\)
  2. B \((3, 6)\)
  3. C \((6, 3)\)
  4. D \((3, 3)\)
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Answer & Solution

Correct Answer

(D) \((3, 3)\)

Step-by-step Solution

Detailed explanation

\(\sum_{i=1}^{10}\left(x_{i}-5\right)=10\) \(\Rightarrow\) Mean of observation \(\mathrm{x}_{\mathrm{i}}-5=\frac{1}{10} \sum_{\mathrm{i}=1}^{3}\left(\mathrm{x}_{\mathrm{i}}-5\right)=1\) \(\Rightarrow \mu=\) mean of observation \(\left(\mathrm{x}_{\mathrm{i}}-3\right)\)…
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