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JEE Mains · Maths · STD 11 - 1. set theory

ધારો કે \( A=\{x :|x^{2}-10|\le6\} \) અને \( B=\{x :|x-2|>1\}. \) તો ...........

  1. A \( A\cup B=(-\infty,1]\cup(2,\infty) \)
  2. B \( A-B=[2,3) \)
  3. C \( A\cap B=[-4,-2]\cup[3,4] \)
  4. D \( B-A=(-\infty,-4)\cup(-2,1)\cup(4,\infty) \)
Verified Solution

Answer & Solution

Correct Answer

(D) \( B-A=(-\infty,-4)\cup(-2,1)\cup(4,\infty) \)

Step-by-step Solution

Detailed explanation

\( |x^{2}-10|\le6 \) \( -6\le x^{2}-10\le6 \) \( 4\le x^{2}\le16 \) \( A=[-4,-2]\cup[2,4] \) \( |x-2|>1 \) \( B=(-\infty,1)\cup(3,\infty) \) \( A\cup B=(-\infty,1)\cup[2,\infty) \) \( A\cap B=[-4,-2]\cup(3,4] \) \( A-B=[2,3] \) \( B-A=(-\infty,-4)\cup(-2,1)\cup(4,\infty) \)
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