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JEE Mains · Maths · STD 12 - 10. vector algebra

ધારો કે \(\vec{a}=4 \hat{i}+3 \hat{j}\) અને \(\vec{b}=3 \hat{i}-4 \hat{j}+5 \hat{k} \cdot\) જો \(\vec{c}\) એ એવો સદિશ હોય કે જેથી \(\vec{c} \cdot(\vec{a} \times \vec{b})+25=0, \vec{c} \cdot(\hat{i}+\hat{j}+\hat{k})=4\), અને \(\vec{c}\) ની \(\vec{a}\) પરનો પ્રક્ષેપ \(1\) હોય, તો \(\vec{c}\) નો \(\vec{b}\) પરનો પ્રક્ષેપ \(............\) છે.

  1. A \(\frac{5}{\sqrt{2}}\)
  2. B \(\frac{1}{5}\)
  3. C \(\frac{1}{\sqrt{2}}\)
  4. D \(\frac{3}{\sqrt{2}}\)
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Answer & Solution

Correct Answer

(A) \(\frac{5}{\sqrt{2}}\)

Step-by-step Solution

Detailed explanation

\(\overrightarrow{ a } \times \overrightarrow{ b }=15 \hat{ i }-20 \hat{ j }-25 \hat{ k }\) Let \(\quad \vec{c}=x \hat{i}+y \hat{j}+z \hat{k}\) \(\Rightarrow 15 x-20 y-25 z+25=0\) \(\Rightarrow 3 x-4 y-5 z=-5\) Also \(x+y+z=4\)…
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