JEE Mains · Maths · STD 12 - 10. vector algebra
Let \(\vec{a}=4 \hat{i}+3 \hat{j}\) and \(\vec{b}=3 \hat{i}-4 \hat{j}+5 \hat{k}\) and \(\vec{c}\) is a vector such that \(\overrightarrow{ c } \cdot(\overrightarrow{ a } \times \overrightarrow{ b })+25=0, \overrightarrow{ c } \cdot(\hat{ i }+\hat{ j }+\hat{ k })=4\) and projection of \(\overrightarrow{ c }\) on \(\overrightarrow{ a }\) is \(1,\) then the projection of \(\overrightarrow{ c }\) on \(\overrightarrow{ b }\) equals:
- A \(\frac{5}{\sqrt{2}}\)
- B \(\frac{1}{5}\)
- C \(\frac{1}{\sqrt{2}}\)
- D \(\frac{3}{\sqrt{2}}\)
Answer & Solution
Correct Answer
(A) \(\frac{5}{\sqrt{2}}\)
Step-by-step Solution
Detailed explanation
\(\overrightarrow{ a } \times \overrightarrow{ b }=15 \hat{ i }-20 \hat{ j }-25 \hat{ k }\) Let \(\quad \vec{c}=x \hat{i}+y \hat{j}+z \hat{k}\) \(\Rightarrow 15 x-20 y-25 z+25=0\) \(\Rightarrow 3 x-4 y-5 z=-5\) Also \(x+y+z=4\)…
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