ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Maths · STD 12 - 11. three dimension geometry

બિંદુ \((-2,3,5)\) ને સમાવતા તથા બન્ને સમતલો \(2 x+4 y+5 z=8\) અને \(3 x-2 y+3 z=5\) ને લંબ હોય તેવા સમતલનું સમીકરણ \(\alpha x+\beta y+\gamma z+97=0\) હોય, તો \(\alpha+\beta+\gamma=.........\)

  1. A \(18\)
  2. B \(17\)
  3. C \(16\)
  4. D \(15\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(15\)

Step-by-step Solution

Detailed explanation

The equation of plane through \((-2,3,5)\) is \(a(x+2)+b(y-3)+c(z-5)=0\) it is perpendicular to \(2 x+4 y+5 z=8\) and \(3 x-2 y+3 z=5\) \(2 a+4 b+5 c=0\) \(3 a-2 b+3 c=0\)…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app