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JEE Mains · Maths · STD 12 - 11. three dimension geometry

જો બિંદુ \((4,4,3)\) નું રેખા \(\frac{x-1}{2}=\frac{y-2}{1}=\frac{z-1}{3}\) માં પ્રતિબિંબ \((\alpha, \beta, \gamma)\) હોય, તો \(\alpha+\beta+\gamma\) = ___

  1. A 9
  2. B 12
  3. C 7
  4. D 8
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Answer & Solution

Correct Answer

(A) 9

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Detailed explanation

ધારો કે R ના યામ \(R=(2 r+1, r+2,3 r+1)\) \(\because \quad P R\) આપેલી રેખાને લંબ છે. \(\therefore(2 r-3) \cdot 2+(r-2) \cdot 1+(3 r-2) \cdot 3=0\) \(\therefore r=1\) \(\therefore\) R ના યામ \(R=(3,3,4)\) \(\therefore \quad(\alpha, \beta, \gamma)=(2,2,5)\)…
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