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JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant

અહી \(I\) એ \(2 \times 2\) કક્ષાનો  એકમ શ્રેણીક છે અને  \(P=\left[\begin{array}{cc}2 & -1 \\ 5 & -3\end{array}\right] \) છે. તો \(n \in N\) ની કિમંત મેળવો કે જેથી \(P^n =5 I -8 P\) થાય.

  1. A \(8\)
  2. B \(10\)
  3. C \(4\)
  4. D \(6\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(6\)

Step-by-step Solution

Detailed explanation

\(P=\left[\begin{array}{cc}2 & -1 \\ 5 & -3\end{array}\right]\) \(5 I-8 P=\left[\begin{array}{ll}5 & 0 \\ 0 & 5\end{array}\right]-\left[\begin{array}{cc}16 & -8 \\ 40 & -24\end{array}\right]=\left[\begin{array}{ll}-11 & 8 \\ -40 & 29\end{array}\right]\)…
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