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JEE Mains · Chemistry · STD 12 - p -Block elements - ll

સૂચી \(- I\) સાથે સૂચી \(- II\) ને જોડો :
સૂચી \(- I\) તત્વોની ઈલેક્ટ્રોન સંરચના સૂચી \(- II\) \(\Delta_{ i }\) in \(kJ\, mol-1\) માં
\((a)\) \(1 s ^{2} 2 s ^{2}\) \((i)\) \(801\)
\((b)\) \(1 s ^{2} 2 s ^{2} 2 p ^{4}\) \((ii)\) \(899\)
\((c)\) \(1 s^{2} 2 s^{2} 2 p^{3}\) \((iii)\) \(1314\)
\((d)\) \(1 s ^{2} 2 s ^{2} 2 p ^{1}\) \((iv)\) \(1402\)
નીચે આપેલ વિકલ્પોમાંથી સાચો જવાબ પસંદ કરો.

  1. A \(( a ) \rightarrow( ii ),( b ) \rightarrow( iii ),( c ) \rightarrow( iv ),( d ) \rightarrow( i )\)
  2. B \(( a ) \rightarrow( i ),( b ) \rightarrow( iv ),( c ) \rightarrow( iii ),( d ) \rightarrow( ii )\)
  3. C \(( a ) \rightarrow( i ),( b ) \rightarrow( iii ),( c ) \rightarrow( iv ),( d ) \rightarrow( ii )\)
  4. D \((a) \rightarrow( iv ),( b ) \rightarrow( i ),( c ) \rightarrow( ii ),( d ) \rightarrow( iii )\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(( a ) \rightarrow( ii ),( b ) \rightarrow( iii ),( c ) \rightarrow( iv ),( d ) \rightarrow( i )\)

Step-by-step Solution

Detailed explanation

\((a)\) \(1 s ^{2} 2 s ^{2} \rightarrow Be\) \((b)\) \(1 s ^{2} 2 s ^{2} 2 p ^{4} \rightarrow O\) \((c)\) \(1 s ^{2} 2 s ^{2} 2 p ^{3} \rightarrow N\) \((d)\) \(1 s ^{2} 2 s ^{2} 2 p ^{1} \rightarrow B\) The ionization enthalpy order is \(B < Be < O < N\) Be has more IE compared…
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