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JEE Mains · Chemistry · STD 11 - 4. Chemical bonding and molecular structure

નીચેનામાં સાચો બંધ ઓર્ડરનો ક્રમ છે:

  1. A \({O}_{2}^{+}>{O}_{2}>{O}_{2}^{-}>{O}_{2}^{2-}\)
  2. B \({O}_{2}>{O}_{2}^{-}>{O}_{2}^{2-}>{O}_{2}^{+}\)
  3. C \({O}_{2}^{2-}>{O}_{2}^{+}>{O}_{2}^{-}>{O}_{2}\)
  4. D \({O}_{2}^{+}>{O}_{2}^{-}>{O}_{2}^{2-}>{O}_{2}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \({O}_{2}^{+}>{O}_{2}>{O}_{2}^{-}>{O}_{2}^{2-}\)

Step-by-step Solution

Detailed explanation

\(\sigma_{1 s}^{2}, \sigma_{1 s}^{* 2}, \sigma_{2 s}^{2}, \sigma_{2 s}^{*}, \sigma_{2 p_{2}}^{2}\) \(\pi_{2 p_{x}}^{2}=\pi_{2 p_{y}}^{2}, \pi_{2 p_{x}}^{*_{1}}=\pi_{2 p_{y}}^{*_{1}}, \sigma_{2 p_{2}}^{*}\) Bond order of \({O}_{2} \Rightarrow 2\) Bond order of…
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