મિથેન અને ઇથેનની પરમાણ્વિયકરણ ઉષ્મા અનુક્રમે \(360\,kJ/mol\) અને \(620\,kJ/mol,\) છે. તો \(C-C\) બંધ તોડવા જરૂરી સૌથી લાંબી તરંગલંબાઇ જણાવો. (એવોગેડ્રો આંક\( = 6.02 \times 10^{23},\) \(h = 6.62 \times 10^{-34}\,Js\) )

A \(2.48 \times 10^4\,\,nm\)
B \(1.49 \times 10^3\,\,nm\)
C \(2.48 \times 10^3\,\,nm\)
D \(1.49 \times 10^4\,\,nm\)

Verified Solution

Answer & Solution

Correct Answer

(B) \(1.49 \times 10^3\,\,nm\)

Step-by-step Solution

Detailed explanation

In \(C{H_4},\,4 \times B{E_{(C - H)}} = 360\,kJ/mol\) \(\therefore \,B{E_{(C - H)}} = 90{\kern 1pt} kJ/mol\) In \({C_2}{H_6},\,B{E_{(C - C)}} + 6 \times B{E_{(C - H)}} = 620\,kJ/mol\) \(\therefore \,B{E_{(C - C)}} = 80{\kern 1pt} kJ/mol\)…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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યાદી - I ને યાદી - II સાથે જોડો.

યાદી - I	યાદી - II
(A) શૂન્યાવકાશની પરમિએબિલિટી	(I) \(\left[\mathrm{M} \mathrm{~L}^2 \mathrm{~T}^{-2}\right]\)
(B) ચુંબકીય ક્ષેત્ર	(II) \(\left[\mathrm{M} \mathrm{~T}^{-2} \mathrm{~A}^{-1}\right]\)
(C) ચુંબકીય મોમેન્ટ	(III) \(\left[\mathrm{M} \mathrm{~L} \mathrm{~T}^{-2} \mathrm{~A}^{-2}\right]\)
(D) વળ અચળાંક	(IV) \(\left[\mathrm{L}^2 \mathrm{~A}\right]\)

નીચે\(\text{ }\)આપેલા\(\text{ }\)વિકલ્પોમાંથી\(\text{ }\)સાચો\(\text{ }\)જવાબ\(\text{ }\)પસંદ\(\text{ }\)કરો\(\text{ }\):

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