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JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)

એક લિટર બફર દ્રાવણ એ \(NH _3\) અને \(NH _4 Cl\) દરેકના \(0.1\,mole\) ધરાવે છે. તેમાં દ્રાવ્ય વાયુમય \(HCl\) ના \(0.02\,mole\) ને ઓગાળતા, દ્રાવણની \(pH ...........\times 10^{-3}\) મળે છે. (નજીકનો પૂર્ણાક) \(\left[\right.\) આપેલ : \(pK _{ b }\left( NH _3\right)=4.745\) \(\log 2=0.301\) \(\log 3=0.477\) \(T =298\,K ]\)

  1. A \(9080\)
  2. B \(9079\)
  3. C \(9081\)
  4. D \(9082\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(9079\)

Step-by-step Solution

Detailed explanation

In resultant solution \(n _{ NH _3}=0.1-0.02=0.08\) \(n _{ NH _4 Cl }= n _{ NH _4^{+}}=0.1+0.02=0.12\) \(pOH = pK _{ b }+\log \frac{\left[ NH _4^{+}\right]}{\left[ NH _3\right]}\) \(=4.745+\log \frac{0.12}{0.08}\) \(=4.745+\log \frac{3}{2}\) \(=4.745+0.477-0.301\) \(pOH =4.921\)…
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