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JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry

આપેલ \(C_{(graphite)} +O_2(g) \rightarrow CO_2(g)\,;\) \(\Delta _rH^o=-395.5 \, kJ\,mol^{-1}\) \(H_2 (g) + \frac{1}{2} O_2 (g) \rightarrow H_2O(l)\,;\)   \(\Delta _rH^o  =-285.8\, kJ\, mol^{-1}\) \(CO_2(g) + 2H_2O(l) \rightarrow CH_4(g) + 2O_2(g)\,;\) \(\Delta _rH^o  = + 890.3\, kJ\, mol^{-1}\) ઉપર દર્શાવેલ થર્મોરાસાયણિક સમીકરણોને આધારે \(298\, K\) તાપમાને પ્રક્રિયા \(C_{(graphite)} + 2H_2(g) \rightarrow CH_4(g) \)  માટે \(\Delta_{r} H^{\circ}\) ની કિંમત ........... \(kJ \,mol^{-1}\)

  1. A \(+ 74.8\)
  2. B \(+ 144.0\)
  3. C \(- 74.8\)
  4. D \(- 144.0\)
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Answer & Solution

Correct Answer

(C) \(- 74.8\)

Step-by-step Solution

Detailed explanation

\(C(graphite) +\mathrm{O}_{2}(\mathrm{g}) \rightarrow \mathrm{CO}_{2}(\mathrm{g})\) \(\Delta_{r} H^{\circ}=-393.55\,\mathrm{kJ}\, \mathrm{mol}^{-1}\) \(\mathrm{H}_{2}(\mathrm{g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{g}) \rightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{l}) ; \)…
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