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JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)

આ પ્રક્રિયાનો વિચાર કરો \(\mathrm{X}_2 \mathrm{Y}(\mathrm{~g})=\mathrm{X}_2(\mathrm{~g})+\frac{1}{2} \mathrm{Y}_2(\mathrm{~g})\)
\(\mathrm{X}_2 \mathrm{Y}(\mathrm{g})\) ના વિઘટન અંશ (x) અને તેના સંતુલન અચળાંક Kp વચ્ચેનો સાચો સંબંધ દર્શાવતું સમીકરણ ______ છે.
ધારો કે \(x\) ખૂબ જ નાનો છે.

  1. A \(x=\sqrt[3]{\frac{2 \mathrm{Kp}}{\mathrm{p}}}\)
  2. B \(x=\sqrt[3]{\frac{2 \mathrm{Kp}^2}{\mathrm{p}}}\)
  3. C \(x=\sqrt[3]{\frac{\mathrm{Kp}}{\mathrm{p}}}\)
  4. D \(x=\sqrt[3]{\frac{K \mathrm{p}}{2 \mathrm{p}}}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(x=\sqrt[3]{\frac{2 \mathrm{Kp}^2}{\mathrm{p}}}\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & 1 \mathrm{~mol} \\ & \mathrm{X}_2 \mathrm{Y}(\mathrm{g}) \rightarrow \underset{\mathrm{x}}{\mathrm{X}} \mathrm{X}_2(\mathrm{~g})+\frac{1}{2} \mathrm{Y}_2(\mathrm{~g}) \\ & \frac{\mathrm{x}}{2} \\ & \therefore \quad P_{\mathrm{x}_2 \mathrm{y}} \\ &…

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