ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry

\(100\, mL\) \(FeCl_3\, (aq)\) ના દ્રાવણમાં વધુ પડતો \(NaOH\, (aq)\) ઉમેરતા \(2.14\, g\) \(Fe(OH)_3\) મળે છે. તો \(FeCl_3\, (aq)\) ની મોલારિટી  .............. \(\mathrm{M}\) થશે.  \((\) મોલર દળ \(Fe=56\, g\, mol^{-1}\), \(Cl=35.5\, g\, mol^{-1})\)

  1. A \(0.2\)
  2. B \(0.3\)
  3. C \(0.6\)
  4. D \(1.8\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(0.2\)

Step-by-step Solution

Detailed explanation

\(\underset{\begin{smallmatrix} \lim iting \\ reagent \end{smallmatrix}}{\mathop{FeC{{l}_{3}}(aq.)}}\,+\underset{\begin{smallmatrix} (Excess\,amount) \\ not\,behave\,as \\ \lim iting\,reagent \end{smallmatrix}}{\mathop{3NaOH(aq.)}}\,\to \) \(Fe{(OH)_3}(s) + 3NaCl(aq.)\) Moles of…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app