ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics

\(\log _{10} K\) વિરુધ્ધ \(\frac{1}{T}\) નો આલેખ સીધી રેખા આપે છે. આંતછેદ અને ઢાળ અનુકમે શોધો. (જ્યાં K સંતુલન અચળાંક છે.)

  1. A \(\frac{2.303R}{\Delta H^{\circ}}, \frac{2.303R}{\Delta S^{\circ}}\)
  2. B \(\frac{\Delta S^{\circ}}{2.303R}, -\frac{\Delta H^{\circ}}{2.303R}\)
  3. C -\(\frac{\Delta S^{\circ}R}{2.303}, \frac{\Delta H^{\circ}R}{2.303}\)
  4. D \(-\frac{\Delta H ^{\circ}}{2.303 R }, \frac{\Delta S ^{\circ}}{2.303 R }\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{\Delta S^{\circ}}{2.303R}, -\frac{\Delta H^{\circ}}{2.303R}\)

Step-by-step Solution

Detailed explanation

\(log_{10} K = -\frac{\Delta H^{\circ}}{2.303RT} + \frac{\Delta S^{\circ}}{2.303 R}\) \(y\)-આંતરછેદ \(= \frac{\Delta S^{\circ}}{2.303 R}\) ઢાળ \(= -\frac{\Delta H^{\circ}}{2.303 R}\)
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app