ExamBro
ExamBro
enEnglishguગુજરાતી
GUJCET · Maths · Continuity and Differentiability

જો \(f(x)=4 x^3+3 x^2+3 x+4, x \neq 0\) તો, \(\frac{d}{d x}\left(x^3 \cdot f\left(\frac{1}{x}\right)\right)=\) _________

  1. A \(24 x^5+15 x^4+12 x^3+12 x^2\)
  2. B \(\frac{x^2}{12}+\frac{x}{6}+\frac{1}{3}\)
  3. C \(\frac{12}{x^2}+\frac{6}{x}+3\)
  4. D \(12 x^2+6 x+3\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(12 x^2+6 x+3\)

Step-by-step Solution

Detailed explanation

\(f\left(\frac{1}{x}\right) = 4\left(\frac{1}{x}\right)^3 + 3\left(\frac{1}{x}\right)^2 + 3\left(\frac{1}{x}\right) + 4 = \frac{4}{x^3} + \frac{3}{x^2} + \frac{3}{x} + 4\) \(x^3 \cdot f\left(\frac{1}{x}\right) = x^3 \left(\frac{4}{x^3} + \frac{3}{x^2} + \frac{3}{x} + 4\right) = 4 + 3x + 3x^2 + 4x^3\)
From GUJCET
Explore more questions on app