WBJEE · Physics · Work Power Energy
The force \(\mathrm{F}\) acting on a particle moving in a straight line is shown below. What is the work done by the force on the particle in the \(1^{\text {st }}\) meter of the trajectory?
- A \(5 \mathrm{~J}\)
- B \(10 \mathrm{~J}\)
- C \(15 \mathrm{~J}\)
- D \(2.5 \mathrm{~J}\)
Answer & Solution
Correct Answer
(D) \(2.5 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
Work done in 1 meter \(=\) area of shaded curve \(=1 / 2 \times 1 \times 5=2.5 \mathrm{~J}\)
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