WBJEE · Maths · Differential Equations
If \(x=\int_0^y \frac{1}{\sqrt{1+9 t^2}} d t\) and \(\frac{d^2 y}{d x^2}=a y\), then \(a\) is equal to
- A \(3\)
- B \(6\)
- C \(9\)
- D 1
Answer & Solution
Correct Answer
(C) \(9\)
Step-by-step Solution
Detailed explanation
\(\Rightarrow \frac{d y}{d x}=\sqrt{1+9 y^2} \Rightarrow \frac{d^2 y}{d x^2}=9 y\)
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