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WBJEE · Maths · Differential Equations

If \(x=\int_0^y \frac{1}{\sqrt{1+9 t^2}} d t\) and \(\frac{d^2 y}{d x^2}=a y\), then \(a\) is equal to

  1. A \(3\)
  2. B \(6\)
  3. C \(9\)
  4. D 1
Verified Solution

Answer & Solution

Correct Answer

(C) \(9\)

Step-by-step Solution

Detailed explanation

\(\Rightarrow \frac{d y}{d x}=\sqrt{1+9 y^2} \Rightarrow \frac{d^2 y}{d x^2}=9 y\)