WBJEE · Physics · Oscillations
When a particle executing SHM oscillates with a frequency \(v\), then the kinetic energy of the particle
- A changes periodically with a frequency of \(v\)
- B changes periodically with a frequency of \(2 \mathrm{v}\)
- C changes periodically with a frequency of \(\mathrm{v} / 2\)
- D remains constant
Answer & Solution
Correct Answer
(B) changes periodically with a frequency of \(2 \mathrm{v}\)
Step-by-step Solution
Detailed explanation
We know that Kinetic energy \(K=\frac{1}{2} m u^{2}\) where \(u=\frac{d y}{d t}=\omega a \cos \omega t\) So. \(K=\frac{1}{2} m \omega^{2} a^{2} \cos ^{2} \omega t\) Hence, kinetic energy varies periodically with double the frequency of SHM. So, when a particle executing SHM…
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