WBJEE · Physics · Electrostatics
In a region, the intensity of an electric field is given by \(\mathbf{E}=2 \mathbf{i}+3 \mathbf{j}+\mathbf{k}\) in \(\mathrm{NC}^{-1}\). The electric flux through a surface \(\mathbf{S}=10 \mathbf{i} \mathrm{m}^{2}\) in the region is
- A \(5 \mathrm{Nm}^{2} \mathrm{C}^{-1}\)
- B \(10 \mathrm{Nm}^{2} \mathrm{C}^{-1}\)
- C \(15 \mathrm{Nm}^{2} \mathrm{C}^{-1}\)
- D \(20 \mathrm{Nm}^{2} \mathrm{C}^{-1}\)
Answer & Solution
Correct Answer
(D) \(20 \mathrm{Nm}^{2} \mathrm{C}^{-1}\)
Step-by-step Solution
Detailed explanation
Given \(\mathbf{E}=(2 \mathbf{i}+3 \mathbf{j}+\mathbf{k}) \mathrm{NC}^{-1}\) and \(\quad \mathrm{S}=10 \mathrm{i} \mathrm{m}^{2}\) We know that…
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